Answer: -
The electronic configuration of Cd²⁺ = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰
Explanation: -
The electronic configuration of Cd = [Kr] 4 d¹⁰ 5 s ²
For the valency to be 2+, Cd must lose 2 electrons.
The electronic configuration of Cd²⁺ = [Kr] 4 d¹⁰
Thus the full electronic configuration is 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰
