Respuesta :
Answer:
Explanation: 25 %
The efficiency of an engine is defined as:
[tex]\eta=1-\frac{T_c}{T_h}[/tex]
where
[tex]T_c[/tex] is the exhaust temperature
[tex]T_h[/tex] is the input temperature
In this problem, the exhaust temperature is 600 K, while the input temperature is 800 K, so the efficiency is
[tex]\eta=1-\frac{600 K}{800 K}=1-0.75=0.25[/tex]
so, the efficiency in % is 25 %.