You are performing a reaction with 1.7 moles of hydroiodic acid and 3.43 moles of zinc bromide: 2HI + ZnBr2 → 2HBr + ZnI2.

How many moles of zinc iodide can be made?

Respuesta :

Moles are the quantity of a substance that is found in the atom or the molecules. 0.85 moles of zinc iodide will be produced from the reaction between hydroiodic acid and zinc bromide.

What are moles?

Moles are the unit of the amount of the substance that measures the amount of the entities like the atoms or the molecules in a compound.

The balanced chemical reaction is shown as,

[tex]\rm 2HI + ZnBr_{2} \rightarrow 2HBr + ZnI_{2}[/tex]

Given,

Moles of hydroiodic acid = 1.7 moles

Moles of zinc bromide = 3.43 moles

From the reaction, it can be said that 2 moles of hydroiodic acid need 1 mole of zinc bromide.

So, the moles of zinc bromide that will react in the reaction are:

[tex]\dfrac{1.7}{2} = 0.85 \;\rm moles[/tex]

Hence, hydroiodic acid is a limiting reactant, and zinc bromide will remain in the reaction as it is an excess reagent.

Moles of zinc iodide is calculated from the limiting reagent:

[tex]\dfrac{1.7}{2} = 0.85 \;\rm moles[/tex]

Therefore, 0.85 moles of zinc iodide are formed.

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