Answer: 54.86 L
Explanation:
Ideal gas equation:
PV = nRT
P: Pressure = 2.00 atm
V: Volume = ?
n: number of moles,
[tex] n= \frac{\text {Given mass}}{\text{Molar mass}} = \frac{18.0 g}{4.0 g/mol} = 4.5 mol [/tex]
R: Gas constant = 0.0821 Latm/molK
T: Temperature = 297 K
[tex]V = \frac{4.5 mol \times 0.0821 L atm/molK \times 297 K}{2.00 atm} = 54.86 L[/tex]
