The answer is D) 1/2.
If each allele confers a unit of color darkness, then only genotypes S2S3 and S1S4 will have 5 units of color darkness because in genotype S2S3 S2 will have 2 units, and S3 will have 3 units, which is 5 units in total. The similar math is for genotypes S1S4.
Now, let's cross S1S3 and S2S4:
Parents: S1S3 x S2S4
Offspring: S1S2 S1S4 S2S3 S3S4
The offspring with genotype S1S2 will have 3 units of color darkness. The offspring with genotype S1S4 will have 5 units, as well as the offspring with genotype S2S3. The offspring with genotype S3S4 will have 7 units.
It can be assumed that only 2 genotypes out of 4 will have 5 units:
2/4 = 1/2.