Answer: The volume when the pressure and temperature has changed is 1332.53 L
Explanation:
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law. The equation follows:
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1,V_1\text{ and }T_1[/tex] are the initial pressure, volume and temperature of the gas
[tex]P_2,V_2\text{ and }T_2[/tex] are the final pressure, volume and temperature of the gas
We are given:
[tex]P_1=0.950atm\\V_1=200L\\T_1=27^oC=[273+27]K=300K\\P_2=0.125atm\\V_2=?L\\T_2=-10^oC=[273-10]K=263K[/tex]
Putting values in above equation, we get:
[tex]\frac{0.950atm\times 200L}{300K}=\frac{0.125\times V_2}{263K}\\\\V_2=1332.53L[/tex]
Hence, the volume when the pressure and temperature has changed is 1332.53 L
