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Assume there is a variable, h already associated with a positive integer value. Write the code necessary to count the number of perfect squares whose value is less than h, starting with 1. (A perfect square is an integer like 9, 16, 25, 36 that is equal to the square of another integer (in this case 3*3, 4*4, 5*5, 6*6 respectively).) Assign the sum you compute to a variable q For example, if h is 19, you would assign 4 to q because there are perfect squares (starting with 1) that are less than h are: 1, 4, 9, 16.

Respuesta :

Answer:

// code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables

int h,q=0,i=1;

cout<<"Enter the value of h:";

// read the value of h

cin>>h;

// find number of perfect square number less than h

do{

    i++;

    q++;

   

}while(i*i<h);

// print the count

cout<<"number of perfect square less than "<<h<<" are:"<<q<<endl;

return 0;

}

Explanation:

Read value of h from user.check each number from 1 to h, if any one is perfect square then increment the value of q.Then print the value of q.

Output:

Enter the value of h:19                                                                                                    

number of perfect square less than 19 are:4

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