Two true-breeding Drosophila are crossed: a normal-winged, red-eyed female and a miniature-winged, vermilion-eyed male. The F1s all have normal wings and red eyes. When F1 offspring are crossed with miniature-winged, vermilion-eyed flies, the following offspring resulted: 233 normal wing, red eye; 247 miniature wing, vermilion eye; 7 normal wing, vermilion eye; 13 miniature wing, red eye. From these results, you could conclude that the alleles for normal wings and red eyes are ___________.

Respuesta :

Answer:

The alleles for normal wing, would be – Nm (Where N represent normal wing and m represents miniature wings)

The alleles for red eye, would be- Rv (Where R represents red eye and v represents vermilion eye)

Explanation:

The alleles are heterogeneous, that is, they possess a dominant and recessive gene. This is because of the result of the F1 generation, which was, Normal winged with red eyes. This clearly proves that the miniature wings are recessive to the normal wings, and the vermilion eye is recessive to the red eye.  

The proof of the allele’s heterogeneous state is shown in the next crossing of the F1 generation with miniature winged, vermilion-eyed flies, where their offspring expressed the recessive genes. Take note, recessive genes can only be expressed when the pair of alleles are both recessive