Respuesta :
Answer:
[tex]\mu=0.11[/tex]
Explanation:
It is given that,
Initial speed of the car, u = 25 m/s
Final speed of the car, v = 0 (it stops)
Distance travelled by the car when it slides, d = 275 m
Mass of the car, m = 755 kg
Let a is the acceleration of the car. Using the third equation of motion to find it as :
[tex]a=\dfrac{v^2-u^2}{2d}[/tex]
[tex]a=\dfrac{0-(25)^2}{2\times 275}[/tex]
[tex]a=-1.13\ m/s^2[/tex]
The car is decelerating.
Let [tex]\mu[/tex] is the coefficient of kinetic friction between the tires and the road. So,
[tex]\mu mg=ma[/tex]
[tex]\mu=\dfrac{a}{g}[/tex]
[tex]\mu=\dfrac{1.13}{9.8}[/tex]
[tex]\mu=0.11[/tex]
So, the coefficient of kinetic friction between the tires and the road is 0.11. Hence, this is the required solution.
