Respuesta :
Answer:
Data:- F=2000N m=0.04kg s=10m vi=o(mass is initially at rest) to find vf=? and t=?
Explanation:
solution :- F=ma to find acceleration a=f/m ,a=2000/0.04=50000 a=50000m/sec² now find time according second eq of motion s=vit+1/2at², 10=0×t +1/2 50000 ×t² ,10=25000×t² ,t²=10÷25000=0.0004 sq root on bothside
[tex]t {}^{2} = \sqrt{0.0004} [/tex]
t=0.02sec now find vf so according to first eq of motion vf=vi+at , vf=0+50000×0.02=1000m/sec acceleration=50000m/sec²,t=0.02sec and vf=1000m/s.
