Answer:
188 atm
Explanation:
Given data
- Mass of O₂ (m): 2.50 × 10³ g
- Temperature (T): 20.0°C + 273.15 = 293.2 K
The molar mass of O₂ is 32.00 g/mol. The moles of O₂ are:
2.50 × 10³ g × (1 mol/ 32.00 g) = 78.1 mol
We can find the pressure exerted by the oxygen using the ideal gas equation.
P × V = n × R × T
P = n × R × T / V
P = 78.1 mol × (0.0821 atm.L/mol.K) × 293.2 K / 10.0 L
P = 188 atm
