A car is initially moving at 20 m/s east and a little while later it is moving at 10 m/s north. Which of the following best describes the orientation of the average acceleration during this time interval?

a.northeast

b.northwest

c.west

d.north of west

Respuesta :

Answer:d

Explanation:

Given

First car is moving  towards east with velocity 20 m/s

[tex]\vec{v_1}=20\hat{i}[/tex]

then it turns towards north then velocity is  

[tex]\vec{v_2}=10\hat{j}[/tex]

suppose car takes t sec to change its path so average acceleration is given by

[tex]a=\frac{v_2-v_1}{t}[/tex]

[tex]a=\frac{1}{t}(10\hat{j}-20\hat{i})[/tex]

So average  acceleration is towards North of west.