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Air enters a compressor with a pressure of 14.7 lbf/in.2 , a temperature of 70F, and a volumetric flow rate of 40 ft3 /s. Air exits the compressor at 50 lbf/in.2 and 190F. Heat transfer from the compressor to its surroundings occurs at a rate of 20.5 Btu per lb of air flowing. Determine the compressor power, in hp, for steady-state operation.

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abdullahfarooqi

Answer:

210 hp

Explanation:

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onyebuchinnaji

The compressor power for steady-state operation is 210.1 hp.

Heat flow rate at the inlet and outlet temperature and pressure

The heat flow rate at the inlet temperature and pressure is calculated as follows;

From steam-table, at 14.7 psi and 70 F, h₁ = 126.34 Btu/lbm

                               at 50 psi and 190 F, h₂ = 155.42 Btu/lbm

Conservation of energy

The rate of energy flow in the compressor can be determined from the principle of conservation of energy for steady-state operation.

m₁h₁ + W = m₂h₂ + mQc

W = m(h₂ - h₁) + mQc

Mass flow rate

m' = ρV

m' = 40 x 0.07488 = 2.995 lb/s

W = 2.995(155.42 - 126.34 ) + 2.995(20.5)

W = 148.5 Btu/s

Convert the heat flow rate to horse power

1 Btu/s = 1.41485 hp

148.5 Btu/s x 1.41485 hp/ Btu/s = 210.1 hp

Thus, the compressor power for steady-state operation is 210.1 hp.

Learn more about heat flow rate in compressors here: brainly.com/question/24356835

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