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In peas, a gene controls flower color such that R = purple and r = white. In an isolated pea patch, there are 36 purple-flowering plants and 64 white-flowering plants. Assuming Hardy-Weinberg equilibrium, what is the value of q for this population?
a. 0.36.
b. 0.64 .
c. 0.75.
d. 0.80.

Respuesta :

Answer:

D

Explanation:

R= Purple,

r= white

Let  q for recessive allele and p for dominant allele

p+q=1

Frequency of q²= 64/100= 0.64

So the frequency of the recessive genotype is 0.64 , that is, the frequency of qq(q²) is 0.64.  

So by Hardy-Weinberg equilibrium

Therefore, the frequency of the recessive allele,  usually called q, is √0.64= 0.80

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