Answer: 82.8 grams of [tex]CaO_2[/tex] are there in [tex]6.90\times 10^{23}[/tex] molecules of
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given molecules}}{\text {avogadro's number}}=\frac{6.90\times 10^{23}}{6.023\times 10^{23}}=1.15moles[/tex]
1 mole of [tex]CaO_2[/tex] weighs = 72 g
1.15 moles of [tex]CaO_2[/tex] weighs =[tex]\frac{72}{1}\times 1.15=82.8g[/tex]
Thus 82.8 grams of [tex]CaO_2[/tex] are there in [tex]6.90\times 10^{23}[/tex] molecules of
