Answer:
4
Option A is the right option.
solution,
∆ABC~∆EDC
[tex] \frac{bc}{cd} = \frac{ac}{ec} \\ \: [/tex]
putting the values,
[tex] \frac{20 - x}{x} = \frac{20}{5} \\ or \: 5(20 - x) = 20x(cross \: multiplication) \\ or \: 100 - 5x = 20x \\ or \: - 5x - 20x = - 100 \\ or \: \: - 25x = - 100 \\ \: or \: x = \frac{ - 100}{ - 25} \\ x = 4[/tex]
Hope this helps..
Good luck on your assignment..
