Respuesta :

AL2006
That's not true at all.

If  a=2  and  b=3 . . .  then

             2 · a · b = 12
but
            a²  +  b²  =  13 .

This doesn't satisfy your statement, because 12 and 13 are not equal.

Right off hand, it looks to me as if your statement is true
ONLY if 
                   |a|  =  |b|                 ('a' = plus or minus 'b') 

and NOT for any other pairs of numbers.
apologiabiology
hmm

one solutionm is if both a and b were 0
the resulting equation would be 0=0 which is true
(0,0) is one solution

another is if both a and b are 1
resulting equation would be 2=2 which is true

I just graphed it and the solution is all values such that a=b
so
(a,b)
(1,1)
(2,2)
(π,π)
etc
(1,1) is a solution

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