When 50.0 mL of 1.00 M HCl(aq) and 50.0 mL of 1.00 M NaOH(aq) , both at 22.0 °C, are added to a coffee cup calorimeter, the temperature of the mixture reaches a maximum of 28.9 °C. What is the approximate amount of heat produced by this reaction? The specific heat of solution (4.18 J/g oC) and density of solution (1.00 g/mL)

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Answer:

The heat produced by this reaction is 2887J

Explanation:

The reaction of HCl with NaOH occurs as follows:

HCl + NaOH → H2O + NaCl + ΔH

Where ΔH is released heat due the reaction

The equation of a coffee cup calorimeter is:

Q = C*m*ΔT

Where Q is heat produced,

C is specific heat of the solution (4.18J/g°C),

m is mass of the solution (50mL + 50mL = 100mL = 100g -Because density is 1g/mL)

and ΔT is change in temperature (28.9°C - 22.0°C = 6.9°C)

Replacing:

Q = 4.184J/g°C*100g*6.9°C

Q = 2887J

The heat produced by this reaction is 2887J

The approximate amount of heat produced by the reaction is 2884 J

We'll begin by calculating the mass of the solution.

Volume of HCl = 50 mL

Volume of NaOH = 50 mL

Total volume = 50 + 50 = 100 mL

Density of solution = 1 g/mL

Mass of solution =?

Mass = Density × Volume

Mass = 1 × 100

Mass of solution = 100 g

  • Next, we shall determine the change in the temperature.

Initial temperature (T₁) = 22 °C

Final temperature (T₂) = 28.9 °C

Change in temperature (ΔT) = ?

ΔT = T₂ – T₁

ΔT = 28.9 – 22

ΔT = 6.9 °C

  • Finally, we shall determine the heat produced by the reaction. This can be obtained as follow:

Mass of solution = 100 g

Change in temperature (ΔT) = 6.9 °C

Specific heat capacity (C) = 4.18 J/g°C

Heat (Q) = ?

Q = MCΔT

Q = 100 × 4.18 × 6.9

Q ≈ 2884 J

Thus, the approximate amount of heat produced by the reaction is 2884 J

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