Answer:
[tex] \boxed{\sf Acceleration \ (a) = 2 \ m/s^2} [/tex]
Given:
Initial velocity (u) = 12 m/s
Final velocity (v) = 24 m/s
Time taken (t) = 6 seconds
To Find:
Acceleration (a) of the car
Explanation:
From equation of motion we have:
[tex] \boxed{ \bold{v = u + at}}[/tex]
By substituting value of v, u & t in the equation we get:
[tex] \sf \implies 24 = 12 + 6a \\ \\ \sf \implies 6a + 12 = 24 \\ \\ \sf \implies 6a = 24 - 12 \\ \\ \sf \implies 6a = 12 \\ \\ \sf \implies a = \frac{12}{6} \\ \\ \sf \implies a = 2 \: m {s}^{ - 2} [/tex]
[tex] \therefore[/tex]
Acceleration (a) of the car = 2 m/s²
