Answer:
Step-by-step explanation:
Since you didn't state what you're looking for, I will lost out all the angles in the picture instead.
Given that
∠CEF = 150°
∠ECA = 32°
∠CEA = 180 - ∠CEF(angles in a straight line)
∠CEA = 180 - 150
∠CEA = 30°
∠EAC = 180 - ∠CEA - ∠ECA(angles in a triangle)
∠EAC = 180 - 30 - 32
∠EAC = 118°
∠CAB = 180 - ∠EAC(angles in a triangle)
∠CAB = 180 - 118
∠CAB = 62°
∠ACB = ∠CEA = 30°(similar angles)
∠ABC = 180 - ∠CAB - ∠ACB(angles in a triangle)
∠ABC = 180 - 62 - 30
∠ABC = 88°
∠ECB = ∠ECA + ∠ACB(angles in a triangle)
∠ECB = 32 + 30
∠ECB = 62°
∠CEA + ∠ECB + ∠ABC = 180
30 + 62 + 88 = 180°.
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