Answer:
JK = 50; IJ = 25√3
Step-by-step explanation:
HAVE: sin ∠J = sin 30° = [tex]\frac{IK}{JK}[/tex]
=> [tex]\frac{IK}{JK}=\frac{25}{JK}=\frac{1}{2}=> JK = 25.2 = 50[/tex]
cos ∠J = cos 30° = [tex]\frac{IJ}{JK}[/tex]
=> [tex]\frac{IJ}{JK}=\frac{IJ}{50}=\frac{\sqrt{3} }{2} => IJ = \frac{\sqrt{3} }{2}.50=25\sqrt{3}[/tex]
