Write an equation of the line given an intercepts. Express in standard form.
1. x – intercept is 4 and y – intercept is 3.
2. x – intercept is -2 and y – intercept is 5.

Respuesta :

Answer:

Required equations in standard form are:

1. 3x+4y=12

2. -5x+2y = 10

Step-by-step explanation:

Standard form of equation is given as:

[tex]Ax+By = C[/tex]

1. x – intercept is 4 and y – intercept is 3.

The points will be:

(4,0) and (0,3)

Slope: m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m = \frac{3-0}{0-4}\\m = -\frac{3}{4}[/tex]

Slope intercept form of line is:

[tex]y = mx+b[/tex]

Putting the values of m and b(y-intercept)

[tex]y = -\frac{3}{4}x+3[/tex]

Multiplying whole equation by 4

[tex]4y = -3x+12\\3x+4y = 12[/tex]

2. x – intercept is -2 and y – intercept is 5

The points will be:

(-2,0) and (0,5)

Now

[tex]m = \frac{5-0}{0+2}\\m = \frac{5}{2}[/tex]

Putting the values of m and b in slope intercept form

[tex]y = \frac{5}{2}x+5[/tex]

Multiplying the equation by 2

[tex]2y = 5x+10[/tex]

[tex]-5x+2y=10[/tex]

Hence,

Required equations in standard form are:

1. 3x+4y=12

2. -5x+2y = 10