Respuesta :
Answer:
5log2 + log3
Step-by-step explanation:
Using the rules of logarithms
logx + logy = log(xy)
log[tex]x^{n}[/tex] ⇔ nlogx
Given
log96
Express 96 as a product of its prime factors
96 = [tex]2^{5}[/tex] × 3 , then
log96
= log([tex]2^{5}[/tex] × 3 )
= log[tex]2^{5}[/tex] + log3
= 5log2 + log3
