Respuesta :
Answer: 26.54 grams
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of lithium nitride}=\frac{12.87g}{34.83g/mol}=0.369moles[/tex]
[tex]Li_3N+3H_2O\rightarrow 3LiOH+NH_3[/tex]
[tex]Li_3N[/tex] is the limiting reagent as it limits the formation of product and [tex]H_2O[/tex] is the excess reagent
According to stoichiometry :
As 1 moles of [tex]Li_3N[/tex] give = 3 moles of [tex]LiOH[/tex]
Thus 0.369 moles of [tex]O_2[/tex] give =[tex]\frac{3}{1}\times 0.369=1.108moles[/tex] of [tex]LiOH[/tex]
Mass of [tex]LiOH=moles\times {\text {Molar mass}}=1.108moles\times 23.95g/mol=26.54g[/tex]
Thus 26.54 g of [tex]LiOH[/tex] will be produced from the given mass.
