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How many grams of aluminum hydroxide are produced when 8 moles of aluminum sulfite react in excess sodium hydroxide ?

Respuesta :

Answer:

Number of moles Aluminium sulfide

1 mole of sulfide contains 150 g

Therefore; 16.2/150  

              = 0.108 moles  

The mole ratio of Al2S3 : Al(OH)3 is 1:2

Therefore; moles of Aluminium hydroxide will be;

 = (0.108 × 2)

 = 0.216 moles  

But, 1 mole of  Al(OH)3 contains 77 g

Therefore, the mass of aluminium hydroxide is

  0.216 moles × 77

=  16.632 g

Step-by-step explanation:

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