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An impulse of 12.2kg m/s is delivered to an object whose initial momentum is 4.5kgm/s. What is the object's final momentum?

Respuesta :

Answer:

Object's final momentum = 16.7 kg-m/s

Explanation:

Given that,

Impulse, J = 12.2 kg-m/s

Initial momentum, [tex]P_i=4.5\ kg-m/s[/tex]

We need to find the object's final momentum. We know that the impulse is equal to the change in momentum. So,

Impulse = change in momentum

[tex]J=P_f-P_i\\\\P_f=J+P_i\\\\P_f=12.2+4.5\\\\P_f=16.7\ kg-m/s[/tex]

So, the object's final momentum is 16.7 kg-m/s.

The final momentum of the object will be "16.7 kg-m/s".

Given:

  • Impulse, [tex]J = 12.2 kg-m/s[/tex]
  • Initial momentum, [tex]P_i = 4.5 \ kg-m/s[/tex]

We know the relation,

→ [tex]Impulse = Change \ in \ momentum[/tex]

or,

→ [tex]J = P_f-P_i[/tex]

then,

→ [tex]P_f = J+P_i[/tex]

By substituting the values,

        [tex]= 12.2+4.5[/tex]

        [tex]= 16.7 \ kg-m/s[/tex]

Thus the above answer is right.      

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