Answer:
a
Step-by-step explanation:
the answer is up at the top
The probability that at least 1 doesn't use a computer at work is 0.8065.
The probability that all 5 use a computer in their jobs is 0.1935.
Suppose we let X represent the no. of women that make use of computers at work. A given random variable X which approaches a binomial distribution with the following data n = 5 and p = 0.72 has a probability function:
[tex]\mathbf{P(X=x) = \left \{ {{(^5_x)(0.72)^x(0.28)^{5-x}, \ X = 0,1,2,...5} \atop {0, \ \ \ \ \ \ \ \ \ \ \ \ elsewhere }} \right.}[/tex]
a.)
Then, the probability that at least 1 doesn't use a computer at work can be computed as:
[tex]\mathbf{1-P(X=5) =1 - (^5_5)(0.72)^5(0.28)^{5-5}}[/tex]
[tex]\mathbf{1-P(X=5) =1 - (0.72)^5}[/tex]
[tex]\mathbf{1-P(X=5) =1 - 0.1935}[/tex]
⇒ 0.8065
b.)
The probability that all 5 make use of computers at their job is;
[tex]\mathbf{P(X=5) = (^5_5) (0.72)^5 (0.28)^{5-5}}[/tex]
[tex]\mathbf{P(X=5) = 1 \times (0.72)^5 \times 1}[/tex]
P(X = 5) = 0.1935
Learn more about probability function here:
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