Answer:
2.00 M KOH
Explanation:
Divide moles by volume and make sure your volume is in LITERS, not mL.
0.0400 mol KOH / 0.0200 L = 2.00 M KOH
A sample of 0.0400 mol potassium hydroxide, KOH was dissolved in water to yield 20.0 ml of solution. The molarity of the solution is 2.00 M KOH.
Molarity is the measure of the concentration of any solute in per unit volume of the solution.
[tex]M = \dfrac{n}{V}[/tex]
Given, the 0.0400 mol potassium hydroxide
20.0 ml volume
Putting the values in the equation
[tex]\dfrac{0.0400 mol }{ 0.0200 ml} = 2 M[/tex]
Thus, the molarity of the solution is 2.00 M KOH.
Learn more about molarity
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