for an closed cylinder with radius r cm and height h cm, find the dimensions giving the minimum surface area, given that the volume is 6 cm3

Respuesta :

The dimensions giving the minimum surface area are  r = 0.98 cm approx. and h = 1.998 cm .

What is surface area?

The surface area of a solid object could be a live of the full area that the surface of the article occupies.

Main body:

The surface area of the closed cylinder is given by,

S = 2πr²+2πrh

And volume is given by,

V = πr²h

Where, R is radius and h is height of cylinder.

Volume is given to be  6 cm³.

V = πr²h = 6

h = 6/πr²

Inserting this value of h in Surface area equation, we get,

S = 2πr²+ 2πr ( 6/πr²)

S = 2πr² + 12 /r

Now differentiating wrt x to find minimum, inserting ds/dr = 0 , we get,

4πr = 12/r²

r = (3/π)¹/³

r = 0.98 cm approx.

h = 6/π *(0.98)²

h = 6/3.017

h = 1.998 cm

Hence ,the dimensions giving the minimum surface area are  r = 0.98 cm approx. and h = 1.998 cm .

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