Respuesta :
[tex] (p^{2} + p - 6) - (x) = p - 9
[/tex] is what is asked.
So all you need to do is a value that will result to p - 9.
x = [tex] (p^{2} + p - 6) - p + 9 [/tex] To isolate x we just transpose the values from the other side of the equation and do the opposite operation.
Combine like terms and just copy the terms that do not have similar expressions:
p will cancel out because p - p = 0
-6 and + 9 will come together because they are like terms: -6 + 9 = 3
[tex] p^{2} [/tex] does not have a pair so it will remain as is. you will be left with:
[tex] p^{2} + 3[/tex]
Let us check:
[tex]p^{2} + p - 6[/tex]
- [tex]p^{2} + 0 + 3 [/tex]
----------------------------
[tex]0 + p - 9[/tex] or [tex]p -9[/tex]
So all you need to do is a value that will result to p - 9.
x = [tex] (p^{2} + p - 6) - p + 9 [/tex] To isolate x we just transpose the values from the other side of the equation and do the opposite operation.
Combine like terms and just copy the terms that do not have similar expressions:
p will cancel out because p - p = 0
-6 and + 9 will come together because they are like terms: -6 + 9 = 3
[tex] p^{2} [/tex] does not have a pair so it will remain as is. you will be left with:
[tex] p^{2} + 3[/tex]
Let us check:
[tex]p^{2} + p - 6[/tex]
- [tex]p^{2} + 0 + 3 [/tex]
----------------------------
[tex]0 + p - 9[/tex] or [tex]p -9[/tex]
Answer:
We have to subtract [tex]p^2+3[/tex] from the given expression to obtain a difference of [tex]p-9[/tex]
Step-by-step explanation:
We are given the following information in the question:
We are given an expression:
[tex]p^2 + p -6[/tex]
We subtract [tex]p^2 - 4p[/tex] from the given expression.
[tex]p^2 + p -6 - (p^2 - 4p)\\= (p^2 - p^2) + (p + 4p)-6\\=5p - 6[/tex]
Now, we want to obtain the difference as [tex]p-9[/tex]
Let x be the expression we subtract from the given expression, then we can write:
[tex]p^2 + p -6 - x = p-9\\p^2 +p -6-(p-9) = x\\x = p^2+(p-p)+(-6+9)\\x = p^2+3[/tex]
Thus, we have to subtract [tex]p^2+3[/tex] from the given expression to obtain a difference of [tex]p-9[/tex]