Respuesta :

calculista
the correct question is
The sum of 5 consecutive integers is 505. What is the third number in this sequence?

Let
x-----------> first integer
x+1-----------> second integer
x+2-----------> third integer
x+3-----------> fourth integer
x+4-----------> fifth integer

we know that
x+(x+1)+(x+2)+(x+3)+(x+4)=505
then
5x+10=505----------> x=(505-10)/5---------> x=99

therefore
the third integer is (x+2)------> 99+2=101

the answer is 101




JiminandTaemybias

Answer: The answer is 101!

Step-by-step explanation:

Call the first number in the sequence x

The next integer in the sequence is x + 1

The sum of the 5 consecutive integers is:

x+ (x + 1)+ (x + 2)+ (x + 3)+ (x + 4) = 505

5x + 10= 505

5x = 495

x = 99

Since x is the first number, x + 2 is the third integer.

Thus, the third number in the sequence is 101

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