[tex]\large\boxed{Formula:V= \frac{4}{3}\pi{r}^{3}}[/tex]
Let's substitute the values according to the formula.
Let's solve!
[tex]V=\frac{4}{3}×\pi×{5}^{3}[/tex]
[tex]V=523.59878 \: {units}^{3}[/tex]
Now, well have to round off to the nearest hundredth.
[tex]\boxed{V=523.6 \: {units}^{3}}[/tex]
Hence, the volume of the given sphere is 523.6 cubic units.
Note: If your using π as π you'll get this answer.
