The value of ideal gas constant (R) in Joule is 8.314 Joule [tex]Kelvin^{-1}[/tex][tex]mol^{-1}[/tex]. Now the given expression is 1.00 J. g[tex]g^{-1}.mole^{-1}[/tex]. Where the g represent the temperature. Thus the abbreviated g must have the value 8.314 to satisfy the original value. Thus the temperature scale will be 1 kelvin = 8.314 g. Now 1 kelvin = -272.15°C or in terms of abbreviation of g we can write -272.15 °C = 8.314g, or, 1°C = (-) [tex]\frac{8.314}{272.15}=0.030[/tex]g. Thus the temperature scale of the g scale is 1 kelvin (K) = 8.314g and 1°C = 0.030 g.
Answer:
Explanation:
Hello,
In this case, starting by the ideal gas constant as shown below:
[tex]R=8.314\frac{J}{mol*K}[/tex]
In order to get the requested value, the following conversion should be applied:
[tex]R=8.314\frac{J}{mol*K}*\frac{1K}{8.314G}=1\frac{J}{mol*G}[/tex]
Therefore, the obtained temperature scale implies that:
[tex]1K=8.314G[/tex]
Best regards.
